//  Created by www.dida100.com on 15/11/9.
//  Copyright © 2015年 滴答编程. All rights reserved.
//
 
#include<stdio.h>
#define N 10
int main()
{
    int a[N]={0,1,2,3,4,5,6,7,8,9};
    int i,t;
    printf("原始数组是:\n");
    for(i=0;i<N;i++)
        printf("%d ",a[i]);
    for(i=0;i<N/2;i++)
    {
        t=a[i];
        a[i]=a[N-1-i];
        a[N-1-i]=t;
    }
    printf("\n排序后的数组:\n");
    for(i=0;i<N;i++)
        printf("%d ",a[i]);
    printf("\n");
    return 0;
}