C 语言实例 - 计算两个时间段的差值 计算两个时间段的差值。 实例 #include stdio.h struct TIME{ int seconds; int minutes; int hours;};void differenceBetweenTimePeriod(struct TIME t1, struct TIME t2, struct TIME *diff); int main(){ struct TIME startTime, stopTime, diff; printf("输入开始时间: \n"); printf("输入小时、分钟、秒："); scanf("%d %d %d", startTime.hours, startTime.minutes, startTime.seconds); printf("输入停止时间: \n"); printf("输入小时、分钟、秒: "); scanf("%d %d %d", stopTime.hours, stopTime.minutes, stopTime.seconds); // 计算差值 differenceBetweenTimePeriod(startTime, stopTime, diff); printf("\n差值: %d:%d:%d - ", startTime.hours, startTime.minutes, startTime.seconds); printf("%d:%d:%d ", stopTime.hours, stopTime.minutes, stopTime.seconds); printf("= %d:%d:%d\n", diff.hours, diff.minutes, diff.seconds); return 0;} void differenceBetweenTimePeriod(struct TIME start, struct TIME stop, struct TIME *diff){ if(stop.seconds start.seconds){ --start.minutes; start.seconds += 60; } diff-seconds = start.seconds - stop.seconds; if(stop.minutes start.minutes){ --start.hours; start.minutes += 60; } diff-minutes = start.minutes - stop.minutes; diff-hours = start.hours - stop.hours;} 尝试一下 输出结果为： 输入开始时间: 输入小时、分钟、秒：12 34 55输入停止时间: 输入小时、分钟、秒: 8 12 5差值: 12:34:55 - 8:12:5 = 4:22:50